# X=I identity matrix

1. Oct 23, 2008

### somebody2

If I have ABCXC^-1A^-1B^-1=I (that is C, B, A inverse), can I modify the order so that the AA^-1, BB^-1 are multiplied to get the identity matrix so that I can get it down to X=I?

Last edited: Oct 23, 2008
2. Oct 23, 2008

### nizi

Re: X=i

It's a clue to change the equation so that it keeps the equality.
For example trying premultiplying the inverse of A...

Last edited: Oct 23, 2008
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