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I X-ray diffraction minima?

  1. Sep 21, 2017 #1
    For x-day diffraction maxima we have braggs law
    2d*sinθ = mλ (maxima)

    Is there an analogous law for the minima like
    2d*sinθ = (m+1/2)λ (minima?)

    Thanks!
     
  2. jcsd
  3. Sep 22, 2017 #2

    jtbell

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    Staff: Mentor

    Diffraction gratings don't have a simple alternating maximum/minimum pattern like the two-slit setup does.

    http://hyperphysics.phy-astr.gsu.edu/hbase/phyopt/gratint.html

    What you see are the primary maxima which are very narrow and bright. You don't normally see the secondary maxima and the minima in between them.
     
  4. Oct 14, 2017 #3
    For an ideal, infinite crystal, and using the kinematic theory of x-ray diffraction, there is intensity only at the Bragg positions, and nothing in between. Once you consider real (finite and imperfect) crystals and multiple scattering (dynamical theory of x-ray diffraction), things become a bit more complicated.

    As an example, in surface diffraction, you get something called an "anti-Bragg" position.

    https://en.wikipedia.org/wiki/X-ray_crystal_truncation_rod
     
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