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Xsin(x) = (x-6)^2

  1. Sep 3, 2011 #1
    1. The problem statement, all variables and given/known data
    xsin(x)=(x-6)^2


    This is for a solid of revolution problem, and I am trying to set these equal to eachother to find the points of intersection. How can I solve this equation??????

    Thanks

    2. Relevant equations



    3. The attempt at a solution
     
  2. jcsd
  3. Sep 3, 2011 #2

    gb7nash

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    Homework Helper

    Re: xsin(x)=(x-6)^2

    Do you know newton's method? You'll have to resort to an iterative technique. This can't be solved algebraically.
     
  4. Sep 3, 2011 #3
    Re: xsin(x)=(x-6)^2

    Yeah, I know newtons method, but really would have rather not resorted to that...LoL... anyways, I did not believe it to be solvable algebraically, but then again, I never took a trig class.


    Thanks
     
  5. Sep 3, 2011 #4
    Re: xsin(x)=(x-6)^2

    Maybe if for very minute x value you can set sinx=x ?
     
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