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Y=1/x + 1/(x+1)

  1. Feb 16, 2009 #1
    in try to use curve sketching methods to graph this equation ive come across a problem in


    I have verified this equation for y'' is correct but solving the numerator for critical numbers by hand ?
  2. jcsd
  3. Feb 16, 2009 #2


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    How accurate does the graph need to be?

    I mean you know how the graph 1/x looks like (I hope you do), 1/(x+1) is similar but with an asymptote in x=-1, the graph should be a superposition of these graphs, so if x+1>0, the graph of 1/(x+1) will tend more rapidly to zero than 1/x so it's dominant in the region of x>0, so the tendency of y to zero should be similar to 1/(x+1) from -1 to zero, and for 0<x<<1 the 1/x is dominant.
  4. Feb 16, 2009 #3


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    There several ways to solve x^3+(x+1)^3=0 by hand. i) Multiply it out and factor it. ii) There's a formula to factor the sum of two cubes. Or iii) write it as -x^3=(x+1)^3 and take the cube root. You'll lose the complex roots if you do it that way, but you don't need them for this problem anyway.
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