- #1

aisha

- 584

- 0

My new equation looks like this I am not sure if I did it right

y=-3sin[2(x-30)]+5

what do you think?

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- Thread starter aisha
- Start date

- #1

aisha

- 584

- 0

My new equation looks like this I am not sure if I did it right

y=-3sin[2(x-30)]+5

what do you think?

- #2

whozum

- 2,221

- 1

y=Asin(k(x-c)+b is shifted up b units, scaled vertically by A units, scaled horizontally by k units, and shifted to the right by c units. If c is negative then it is shifted to the left.

- #3

aisha

- 584

- 0

i want c to be negative because it says shift 30 degrees to the left, isn't this correct?

- #4

LENIN

- 102

- 1

- #5

Fermat

Homework Helper

- 872

- 1

sorry, aisha, but your formula "y=-3sin[2(x-30)]+5" isn't correct.aisha said:i want c to be negative because it says shift 30 degrees to the left, isn't this correct?

I just entered "y = -3sin(2x)" and the other one in graphmatica and "y=-3sin[2(x-30)]+5" is definitely shifted to the right!

Edit: it shoulf be "y=-3sin[2(

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