1. The problem statement, all variables and given/known data I had to solve the 2nd order d.e y'' + 4y' + 5y=0 Which I have done, then I need to find a solution for which y(0)=1 and y'(0)=0 3. The attempt at a solution My general soltuion for the d.e is y= e^(-2x) (c_1 *cos(x) + c_2*sin(x)) so for y(0)=1= e^0 (c_1 * 1 + 0) so I end up with c_1=1 but I dont have an answer for c_2, I assume I just can't write c_2 =0? SO that is my first question. My second is how do I solve y'(0)=0 ... it might sound like a silly question but there is no examples in my text and I'm not sure, should I just do this y= e^(-2x) (c_1 *cos(x) + c_2*sin(x)) y'= -e^(-2x)(c_2*cos(x) + 3*c_1*sin(x)) y'(0)=0=-e^0 * (c_2*cos(0) + 0) 0= c_2 So If I'm even on the right track, this means the constant(s) equal zero?