Indicate why we can impose only n initial conditions on a solution of nth order linear differential equation.(adsbygoogle = window.adsbygoogle || []).push({});

A) Given the equation y'' + py'+ qy = 0

explain why the value of y''(a) is determined by the values of y(a) and y'(a).

B) Prove that the equation y'' - 2y' -5y =0

has the solution satisfying the conditions y(0) = 1, y'(0) = 0, and y''(0) = C

if and only if C = 5.

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# Y'' + py'+ qy = 0 explain why the value of y''(a) is determined by the values of y(a)

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