# Y'/y^2 = 1

1. Feb 16, 2017

### johann1301h

1. The problem statement, all variables and given/known data

Solve the differenetial equation and find the all solutions through (1, 0).
y'/y^2 = 1

3. The attempt at a solution

i find one solution: 1/(1-x). But the math book says 1/(1-2x) also is a solution. How do i find this solution?

I used that ∫y-2dy = ∫1dx to find the first solution.

2. Feb 16, 2017

### Ray Vickson

You need to show the actual details of your solution in order for us to see where you went wrong.

3. Feb 16, 2017

### ehild

Is it really a solution? Replace it back into the original equation.

4. Feb 16, 2017

### vela

Staff Emeritus

A solution where $y=0$ at some point? Isn't that a problem with the given differential equation?