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Y'/y^2 = 1

  1. Feb 16, 2017 #1
    1. The problem statement, all variables and given/known data

    Solve the differenetial equation and find the all solutions through (1, 0).
    y'/y^2 = 1

    3. The attempt at a solution

    i find one solution: 1/(1-x). But the math book says 1/(1-2x) also is a solution. How do i find this solution?

    I used that ∫y-2dy = ∫1dx to find the first solution.
     
  2. jcsd
  3. Feb 16, 2017 #2

    Ray Vickson

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    You need to show the actual details of your solution in order for us to see where you went wrong.
     
  4. Feb 16, 2017 #3

    ehild

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    Is it really a solution? Replace it back into the original equation.
     
  5. Feb 16, 2017 #4

    vela

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    A solution where ##y=0## at some point? Isn't that a problem with the given differential equation?
     
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