- #1

- 239

- 0

## Main Question or Discussion Point

4

5

11

34

65

111

175

260

505

540

671

what is the next line

5

11

34

65

111

175

260

505

540

671

what is the next line

- Thread starter ArielGenesis
- Start date

- #1

- 239

- 0

4

5

11

34

65

111

175

260

505

540

671

what is the next line

5

11

34

65

111

175

260

505

540

671

what is the next line

- #2

- 239

- 0

really no one got an idea ?

- #3

- 1

- 0

Is the next number 802.

- #4

- 147

- 1

ArielGenesis, maybe you can give any hint?

- #5

- 239

- 0

1

5

15

34

65

111

175

260

369

505

671

not much diffrent isn't it.

no neveza, it's not 802

the hint is that it involve listing a group of number and doing sum.

- #6

- 918

- 16

1 = 1

5 = 2 + 3

15 = 4 + 5 + 6

34 = 7 + 8 + 9 + 10

65 = 11 + 12 + 13 + 14 + 15

111 = 16 + 17 + 18 + 19 + 20 + 21

175 = 22 + 23 + 24 + 24 + 26 + 27 + 28

260 = 29 + 30 + 31 + 32 + 33 + 34 + 35 + 36

369 = 37 + 38 + 39 + 40 + 41 + 42 + 43 + 44 + 45

505 = 46 + 47 + 48 + 49 + 50 + 51 + 52 + 53 + 54 + 55

671 = 56 + 57 + 58 + 59 + 60 + 61 + 62 + 63 + 64 + 65 + 66

870 = 67 + 68 + 69 + 70 + 71 + 72 + 73 + 74 + 75 + 76 + 77 + 78

- #7

- 222

- 0

4

5

11

34

65

111

175

260

505

540

671

1381

Is that anywhere close? You really don't want to know how my messed up mind found that answer though. It might make you go crazy....

Oopss! You posted another one...

1

5

15

34

65

111

175

260

369

505

671

870

Looks like that should be the answer for this second set of numbers.

5

11

34

65

111

175

260

505

540

671

1381

Is that anywhere close? You really don't want to know how my messed up mind found that answer though. It might make you go crazy....

Oopss! You posted another one...

1

5

15

34

65

111

175

260

369

505

671

870

Looks like that should be the answer for this second set of numbers.

Last edited:

- #8

- 222

- 0

I did it this way:

C = 6 9 12 15 18 21 24 27 30 ??? [ Difference in #'s from B ]

B = 4 10 19 31 46 64 85 109 136 166 ??? [ Difference in #'s from A]

A=1, 5, 15, 34, 65, 111, 175, 260, 369, 505, 671, ???

In C, the ??? should, of course, be 33, which makes the ??? in B = 199, which makes the ??? in A = 870

- #9

- 918

- 16

Rahmuss, your approach is systematic and works in a large number of cases of this kind of puzzle.

- #10

- 239

- 0

can we form a formula based on rahmuss asnwer. as i also had not notice it. and how could it happen to be 3 if he is going to make D = 3,3,3,3,3,3,3 [diffrence in #'s from c]

- #11

- 918

- 16

One possible formula is this difference formula:ArielGenesis said:can we form a formula based on rahmuss asnwer.

[itex]A_n = 3 \times A_{n-1} - 3 \times A_{n-2} + A_{n - 3} + 3;[/itex]

Another would be a cubic polynomial in n, but I haven't figured out the coefficients yet.