For the angles, see this picture: http://www.webassign.net/sf5/p4_13.gif

{a} Yet again, I split the larger triangle in two by using a positive 198N force, making the large triangle's lower 90 degree angle into a 30 degree angle on the left, and a 60 degree angle on the right.

{b1} Thus, for the tension in the left string:

sin(60) = 198N/Hypotenuse

Hyp. = 198N/sin(60)

Hyp. = 228.6N

--Yet, this value is not the answer, and dividing by two does not work in this instance.

{b2} And for the tension in the right string:

cos(30) = 198N/Hyp.

Hyp. = 198N/sin(30)

Hyp. = 396N

-- Again, this is not the right answer, and divding it by two does not work.

What am I doing wrong?