- #1
wetcarpet
- 10
- 0
A 198N bird feeder is supported by three cables. Find the tension in each cable.
For the angles, see this picture: http://www.webassign.net/sf5/p4_13.gif
{a} Yet again, I split the larger triangle in two by using a positive 198N force, making the large triangle's lower 90 degree angle into a 30 degree angle on the left, and a 60 degree angle on the right.
{b1} Thus, for the tension in the left string:
sin(60) = 198N/Hypotenuse
Hyp. = 198N/sin(60)
Hyp. = 228.6N
--Yet, this value is not the answer, and dividing by two does not work in this instance.
{b2} And for the tension in the right string:
cos(30) = 198N/Hyp.
Hyp. = 198N/sin(30)
Hyp. = 396N
-- Again, this is not the right answer, and divding it by two does not work.
What am I doing wrong?
For the angles, see this picture: http://www.webassign.net/sf5/p4_13.gif
{a} Yet again, I split the larger triangle in two by using a positive 198N force, making the large triangle's lower 90 degree angle into a 30 degree angle on the left, and a 60 degree angle on the right.
{b1} Thus, for the tension in the left string:
sin(60) = 198N/Hypotenuse
Hyp. = 198N/sin(60)
Hyp. = 228.6N
--Yet, this value is not the answer, and dividing by two does not work in this instance.
{b2} And for the tension in the right string:
cos(30) = 198N/Hyp.
Hyp. = 198N/sin(30)
Hyp. = 396N
-- Again, this is not the right answer, and divding it by two does not work.
What am I doing wrong?