- #1

tanaygupta2000

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- 14

- Homework Statement
- The two slits in a Young’s double-slit experiment are of unequal width, one being four

time wider than the other. If i(max) and i(min) denote the intensities at a neighbouring

maximum and a minimum, then the ratio i(min)/i(max) is: (a)1/9 (b)1/4 (c)3/5 (d)0 ?

- Relevant Equations
- Intensity, i ∝ (amplitude)^2

Maximum i = i1 + i2

Minimum i = i1 -iI2

Since slit-2 = 4 × (slit-1)

Hence amplitude, a2 = 4a1

which gives i2 = 16×i1

So i(max) = i2 + i1 = 16i1 + i1 = 17i1

& i(min) = i2 - i1 = 16i1 - i1 = 15i1

=> i(min) /i(max) = 15/17

but there's no such option.

Kindly help me to figure out where am I doing error.

Hence amplitude, a2 = 4a1

which gives i2 = 16×i1

So i(max) = i2 + i1 = 16i1 + i1 = 17i1

& i(min) = i2 - i1 = 16i1 - i1 = 15i1

=> i(min) /i(max) = 15/17

but there's no such option.

Kindly help me to figure out where am I doing error.