- #1

thursdaytbs

- 53

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So far, I've said:

F = Y(delta-L / L-naught)A + Y(delta-L / L-naught)A

*Where, the first part is for Aluminum, and the Second part is for Steel.

Manipulating this equation I got:

(2Fx)/A = (6.9E10)(delta-Laluminum) + (4E11)(delta-Lsteel)

and, delta-Aluminum + delta-steel = 0.001m

*where x = the length of steel, therefore aluminum = 2x.

This is where I'm stuck. I dont' know the Force applied, or the Area of the rod. What can i do? Thanks in advance for any help.