Young's modulus of a wire

  • Thread starter cstout
  • Start date
  • #1
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Homework Statement



A wire of length 4.97 m with a cross-sectional area of 0.104 cm2 stretches by 6.52 mm when a load of 0.92 kN is hung from it. What is the Young's modulus for this wire? Answer in Pa

Homework Equations



F/A = Y(Change in L / L)

where F is the magnitude of force
A = .104cm^2
Y= Young's modulus
Change in L = 6.52mm
L = 4.97 m

The Attempt at a Solution



I tried Y = (9025.2 N)(4.97 m) / (.00652 m)(.00104 m^2) but that is wrong
 

Answers and Replies

  • #2
PhanthomJay
Science Advisor
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Check your decimal points. F = 920N and A = .0000104m^2
 
  • #3
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ah.. thanks i got it now
 

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