- #1

- 16

- 0

## Homework Statement

A large 3.00×10^4 L aquarium is supported by four wood posts (Douglas fir) at the corners. Each post has a square 3.80 cm x 3.80 cm cross section and is 80.0 cm tall.

By how much is each post compressed by the weight of the aquarium?

## Homework Equations

deltaL = F*L_0/(Y*A)

Y (for Douglas fir) = 1 * 10^10 N/m^2

## The Attempt at a Solution

This seems very straight forward, I just need to determine F.

F= ma = m(aquarium)g

but, what is the mass of a 3.00×10^4 L aquarium?

once I determine that, I figure it'll just be:

deltaL = ( m * 9.8 * .8)/(.144 * 10^10) meters

=> 5.44*10^10*m meters

How do I find m ??

Thanks for the help!