Young's modulus problem

[ACCC12]

hi

i have been given these results in order to work out the young's modulus can any 1 tell me how i go about doing this

Force (kN) Extension (mm)
0.5 0.003
1 0.011
1.5 0.019
2 0.021
2.5 0.024
3 0.032
3.5 0.040
4 0.043
4.5 0.050
5 0.060
5.5 0.064
6 0.070
6.5 0.076
7 0.081

Area 50mm by 5

thanks for all your help

 

[rock.freak667]

$$E=\frac{stress}{strain}$$


Write the formula for stress and the formula fopr strain and then simply the formula for Young's Modulus,E.

 

[ACCC12]

i know the equation but i didnt know which part of the data to use, do i just take any part of the data from the table or do i have to plot a graph! thanks for all you help!

 

[dk_ch]

i know the equation but i didnt know which part of the data to use, do i just take any part of the data from the table or do i have to plot a graph! thanks for all you help!

what is meant by "area 50mm by 5 " in your data ? please explain.

 

[rock.freak667]

$$E=\frac{\frac{F}{A}}{\frac{e}{l}}$$


$$E=\frac{Fl}{Ae}$$

Right?


From your graph, what does the fraction F/e represent?

 

[ACCC12]

50mm length, 5mm diameter

 

[ACCC12]

got the answer to be 5.3 is that correct!

equation used

2.5 x 50
----------
981.75 x 0.024

 

[ACCC12]

any takers! thanks