Young's modulus problem

  • Thread starter ACCC12
  • Start date
  • #1
5
0
hi

i have been given these results in order to work out the young's modulus can any 1 tell me how i go about doin this

Force (kN) Extension (mm)
0.5 0.003
1 0.011
1.5 0.019
2 0.021
2.5 0.024
3 0.032
3.5 0.040
4 0.043
4.5 0.050
5 0.060
5.5 0.064
6 0.070
6.5 0.076
7 0.081

Area 50mm by 5

thanks for all your help
 

Answers and Replies

  • #2
rock.freak667
Homework Helper
6,230
31
[tex]E=\frac{stress}{strain}[/tex]


Write the formula for stress and the formula fopr strain and then simply the formula for Young's Modulus,E.
 
  • #3
5
0
i know the equation but i didnt know which part of the data to use, do i just take any part of the data from the table or do i have to plot a graph! thanks for all ya help!
 
  • #4
44
0
i know the equation but i didnt know which part of the data to use, do i just take any part of the data from the table or do i have to plot a graph! thanks for all ya help!
what is meant by "area 50mm by 5 " in your data ? please explain.
 
  • #5
rock.freak667
Homework Helper
6,230
31
[tex]E=\frac{\frac{F}{A}}{\frac{e}{l}}[/tex]


[tex]E=\frac{Fl}{Ae}[/tex]

Right?


From your graph, what does the fraction F/e represent?
 
  • #6
5
0
50mm length, 5mm diameter
 
  • #7
5
0
got the answer to be 5.3 is that correct!

equation used

2.5 x 50
----------
981.75 x 0.024
 
  • #8
5
0
any takers! thanks
 

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