Yukawa interaction

1. Oct 9, 2015

AleksanderPhy

Hello There I may have some mistakes so correct me when I wrote something wrong.My question is:what's the yukawa's interaction and why it is not part of standard model?

2. Oct 9, 2015

jk22

I remembered having seen that once it was to compute the fourier transform of the coulomb potential it is like $$V(r)=\frac{e^{-ar}}{r}$$ then you put a to zero after the transform.

3. Oct 9, 2015

AleksanderPhy

Thank you very much(;But what is α
PS! Am I correct that r is radius?

4. Oct 9, 2015

jk22

Right.
a is just some adjustable parameter. There are other threads on the topic too maybe worth to look at them.

5. Oct 9, 2015

AleksanderPhy

Thank you so much it helped me lot.

6. Oct 9, 2015

Matterwave

The Yukawa potential was used early on to model the strong force I believe. The exponentially decaying term gave rise to an exponential weakening of the force (strong force is short distance). But we have a better picture now of the strong force (what with the gluons and stuff). The Yukawa potential itself is just a potential with some functional force, whether nature conforms to this picture is a separate issue.

7. Oct 10, 2015

AleksanderPhy

Thx same words