1. The problem statement, all variables and given/known data Show that the polynomial function: P(x)=x6+2x4+3x2+4 has six nonreal zeros 2. Relevant equations -none- 3. The attempt at a solution I tried using synthetic division with all the possible values it could have(p/q) but none of them worked. I was just wondering what it meant by showing it had six nonreal zeros. Is what I did the right work to show that, or no? My answer: Because all the possible values(±1, ±2, ±4) did not work, it doesn't have any real solutions. Would that be the correct way to answer the question?