Proof that MIT is crap (if I'm nothing without her)

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The discussion explores the equation "Me - She = 0," suggesting that one's identity is tied to another person, particularly in a female context. It raises questions about the implications of this equation, such as whether it indicates a lesbian identity and if all women associated with MIT are lesbians. Participants also critique the mathematical validity of the statements, questioning the non-zero nature of certain variables. The conversation highlights the complexities of identity and relationships through a playful mathematical lens. Overall, the thread combines humor with deeper reflections on gender and identity.
Jin314159
Me - She = 0
Me = She
M = Sh
Mit = Sh...
 
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It only works for females, and you forgot to prove that e is non-zero.

;)
 
Muzza said:
It only works for females, and you forgot to prove that e is non-zero.

;)

I also forgot to show that "-" is a closed operation.
 
.. and that "it" is non zero as well (^_^). Well, just to make it non-trivial.
 
Doesn't Me=She imply lesbians? :confused:
 
If that is correct, would that imply that all Mit-girls lesbians ? :surprise:
:smile:
 
Seemingly by some mathematical coincidence, a hexagon of sides 2,2,7,7, 11, and 11 can be inscribed in a circle of radius 7. The other day I saw a math problem on line, which they said came from a Polish Olympiad, where you compute the length x of the 3rd side which is the same as the radius, so that the sides of length 2,x, and 11 are inscribed on the arc of a semi-circle. The law of cosines applied twice gives the answer for x of exactly 7, but the arithmetic is so complex that the...
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