
#1
Jul2005, 08:05 PM

P: 45

If specs on an appliance plate read ; 15 Amps, 115 Volts.
The distance from the power source to the receptacle (plug) where the appliance is going to be plugged is 230 feet, what is the wire (american wire gage) or conductor size, the thickness of the wire? Thank you. 



#2
Jul2005, 08:52 PM

Sci Advisor
PF Gold
P: 2,631

You can check the distance you can go with this wire gauge calculator
EDIT: Sorry. This calculator is for 24 volt equipment only! Regards 



#3
Jul2005, 09:28 PM

Admin
P: 21,628

Typical household wiring is AWG number 12 or 14.
See if any of these of useful  http://www.faa.gov/certification/air...3/Ch_1105.doc (open directly or save target as), which looks like it gives gauge 8 for 115 V, 240 feet, 15A  but check the Word document. Wire gauge calculator  http://www.powerstream.com/Wire_Size.htm Electrical conductors http://www.tpub.com/content/neets/14176/index.htm http://www.tpub.com/content/neets/14...s/14176_20.htm  Wire gauge table 



#4
Jul2105, 12:27 AM

Sci Advisor
P: 286

calculate wireconductor sizeSome insurance companies will not reimburse for damage if the electrical code is not followed. ... 



#5
Jul2105, 01:54 AM

P: 64

IN THIS CASE TO BE SAFE, WE MUST ALLOW A MAXIMUM VOLTAGE DROP OF 5 VOLTS IN THE CIRCUIT. TAKE A LOOK IN THE FORMULA BELOW.... VD= 2*K*I*L/ CSA WHERE: VD= VOLTAGE DROP I= CURRENT L= DISTANCE OF THE LOAD FROM THE OUTLET (IN FT) K= 12 FOR COPPER AND 19 ALUMINUM (FOR MAXIMUM TEMP OF 75 DC) CSA= CONDUCTOR CROSS SECTIONAL AREA IN CIRCULAR MILS. ***SUPPOSE WE USE COPPER CONDUCTOR AND WE ALLOW A MAXIMUM OF 5V MAX. VOLTAGE DROP: 5= 2*12*15*230/CSA CSA= 82800/5 CSA= 16560 CM FROM COMMERCIAL REFERRENCES: 15560 CM IS CLOSEST TO 16510 CM WHICH IS #8 COPPER OR 8 SQMM WIRE. NOTE: 1. IN THIS CASE A MAXIMUM OF 5 VOLTS WAS CONSIDERED IN THE CALCULATION. 2. THIS CALCULATION IS NOT VALID FOR LARGE MOTORS. BECAUSE MOTORS DRAWS A MAXIMUM OF 7OO% TIMES ITS FULL LOAD TORQUE DEPENDING ON THE MOTOR CONTROL STARTING METHODS USED BY THE DESIGNING ENGINEER. 



#6
Jul2105, 01:58 AM

P: 64

IN THIS CASE TO BE SAFE, WE MUST ALLOW A MAXIMUM VOLTAGE DROP OF 5 VOLTS IN THE CIRCUIT. TAKE A LOOK IN THE FORMULA BELOW.... VD= 2*K*I*L/ CSA WHERE: VD= VOLTAGE DROP I= CURRENT L= DISTANCE OF THE LOAD FROM THE OUTLET (IN FT) K= 12 FOR COPPER AND 19 ALUMINUM (FOR MAXIMUM TEMP OF 75 DC) CSA= CONDUCTOR CROSS SECTIONAL AREA IN CIRCULAR MILS. ***SUPPOSE WE USE COPPER CONDUCTOR AND WE ALLOW A MAXIMUM OF 5V MAX. VOLTAGE DROP: 5= 2*12*15*230/CSA CSA= 82800/5 CSA= 16560 CM FROM COMMERCIAL REFERRENCES: 15560 CM IS CLOSEST TO 16510 CM WHICH IS #8 COPPER OR 8 SQMM WIRE. THEREFORE: USE #8 OR 8.0 sqmm WIRE. NOTE: 1. IN THIS CASE A MAXIMUM OF 5 VOLTS WAS CONSIDERED IN THE CALCULATION. 2. THIS CALCULATION IS NOT VALID FOR LARGE MOTORS. BECAUSE MOTORS DRAWS A MAXIMUM OF 7OO% TIMES ITS FULL LOAD TORQUE DEPENDING ON THE MOTOR CONTROL STARTING METHODS USED BY THE DESIGNING ENGINEER. 



#7
Jul2105, 07:23 PM

P: 45

Thanks to all of you, I got it now.




#8
Jul1406, 04:16 AM

P: 1

Hai
Iam rias iam doing my project on electric trolley bus which should be taking power supply from over head grid supply and running the vehicle through drive motors. In this case iam having various Ac & Dc voltages. I need how to calculate the proper wire size in sqmm. please reply me as soon as possible with proper formulas. I have calculated all the terms as volt,amps,watt,res, ohms etc Regards A.Riaz ahamed 


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