Recent content by 511mev

That is what I thought. I am attempting to help a student with this problem on Cramster. He claims that there is only one answer. I cannot formulate a proof, though.

Are you saying that my assertion that a bound state wave function go to zero at infinity is incorrect? Would not a member of a well chosen L^2 have this property if it were to represent a bound state?

1. Which of the following is an allowed wave function for a particle in a bound state? N is a constant and α, β>0. 1) Ψ=N e-α r 2) Ψ=N(1-e-α r) 3) Ψ=Ne-α x e-β(x2+y2+z2) 4) Ψ=Non-zero constant if r<R , Ψ=0 if r>R Only one is correct. 2. What are the criteria for...