Recent content by 6FX

well, following what you're saying, the v+vo part of the equation I just used corresponds to the "start" and "stop" regions of the ball's path, which is really just saying half the distance of the ball's total path, as it has to travel back down again (notwithsatnding the 1.50metres). I guess I...

Here's how I got 21.1. The units are meters. In order to solve for total distance as the problem asks, I used the equation v^2=vo^2+2ax. Solving for x gives: x=(v^2-vo^2)/(2a). I used v=zero (an assumption on my part), vo=19.6, and a=9.8m/s^2. Plugging all of this in gave x=19.6m. I added this...

Homework Statement A stone is flung straight up from a point 1.50 m above the ground and with an initial speed of 19.6 m/s. a. What is the stone's maximum height above the ground? b. How much time passes before the stone hits the ground? Homework Equations The four kinematic equations...