Recent content by 7even

Oh I get it, thanks so much for the help!

I see. For the first instant; tan10°=550m/x ... x = 3,119.2m tan47.77°=x/150m ... x = 165.25m

Create a right angle triangle; use the vertical length between the submarine and the helicopter and solve for the horizontal distance. Therefore, tan10°=700m/x ... x = 3969.9m

I see, so those angles should be changed from 10 to 80 and 30 to 60. Therefore ∅1 = 47.77° and ∅2=40.63

From the horizontal, so yes, the surface!

Homework Statement A foreign fishing submarine moves straight north through Canadian waters at a constant velocity of 12 m/s and a constant depth of 150m below the surface. A Canadian helicopter is in pursuit, flying in exactly the same direction at a constant velocity of 52 m/s and a constant...