sorry about the late reply,
I only got as far as :
sin 46 = X/H = (H-half lambda)/H
Solved for H and got 468.54
Then: sin 22 = h/H
and got h= 175.5
Is that right?
So, in this diagram half lamda = H-X
so how do we go about finding H or X?
nothing is given...:S
Probably a lot of trigs, do the angles in my second diagram make sence?
If so then I get:
sin 22= hyp (h)/(half lambda +X)
and I don't really know where to go from there..
Sorry, my numbers are different, the angle from horizontal is 22 and my wavelength is 263 m.. so the question would read:
Radio waves of wavelength 263 meters from a star reach a radio telescope by two separate paths. One is a direct path to the receiver which is situated on the edge of a cliff...
I did.. I got 5504.29 as my path diff,
PD= (lambda)^2/4pi
thats from phase difference = half lambda = 2pi PD/lambda
Where am i going wrong?
After I found PD.. from my diagram i found that H= PD sin 22/sin46
Homework Statement
Radio waves of wavelength 250 meters from a star reach a radio telescope by two separate paths. One is a direct path to the receiver which is situated on the edge of a cliff by the ocean. The second is by reflection off the water. The first minimum of destructive...
I'm having trouble with this one, I don't understand how to find the value for the hyp.
I just found phase difference (=half wavelength) and found path difference (from: phase difference = 2pi*phase difference/wavelength)
Then I used height = phase difference*sin theta
any advice?
Homework Statement
A violin string has a length of 0.35m and is tuned to concert G (a frequency of 392Hz). Where must the violionist place her finger to play concert A, with a frequency of 440Hz?
Homework Equations
The Attempt at a Solution
I used v= frequency * wavelength and...