Recent content by A J

Keeping in mind ohms law, how does it draw a fixed amount of power? what's changing to allow current to flow more freely?

Sure, so the photo eye requires that power +/- inefficiencies. I guess i am hung up on how it does this - Where is the reduction of resistance in order to allow more electrons to flow (higher amps). what component of the photo eye allows this to happen.

For those who are asking for the spec sheet. http://www.keyence.com/products/sensor/photoelectric/lr-w/specs/index.jsp

I guess you mean does it show different specs if its signalling or not?

I don't know much about non-linear circuits, can you elaborate on how current can go up as voltage goes down? voltage is the "pressure" and Current is "flow"

I was reading the specs on a photo eye and it states its current consumption 65 mA at 24v 120 mA at 12v both situations end up with roughly 1.56 VA of power...how does it draw more current with less voltage applied. If V=IR, the only way i see it is the resistance of the system must lower...