Recent content by Abanishki

ohh, I believe I get it now :D thanks a lot Simon, VirtuallyReal!

so, you are saying that my initial formula only calculates the probability that balls of the same color as the first ball picked can win?

P(Y=y)=(((9)C(y-1)×(40)C(x-y))/(49)C(x-1)) Does this formula not suffice? I used hypergeometric d, but ignored the first draw. The maximum number of balls that are of the same color is 10 :/

well i figured it needs hypergeometric distribution :S not too sure how to deal with the fact that the same colored balls can be any of the 5 colors...

A bag contains a total of 50 balls (10 red, 10 blue, 10 green, 10 black, 10 white). If I draw x balls from the bag, what is the probability that the largest number of balls that are the same color is y? For example, if I draw 7 balls, and I get 4 Blue, 2 Green, 1 Red, y=4 It'd be nice if you...