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Help finding an indefinite integral
I am trying to find the following indefinite integral: Homework Statement ∫\sqrt{}x/(x-1)dx Homework Equations None The Attempt at a Solution I tried to use substitution but got nowhere. I set u=\sqrt{}x so du=1/(2\sqrt{}x)dx. However from here on on I got stuck. I also tried...- AbsValue13
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- Indefinite Indefinite integral Integral
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- Forum: Calculus and Beyond Homework Help