Recent content by adam74269

  1. adam74269

    Engineering Problem calculating the force on a tube wall

    A-A' (mv1^2)/2-(mv0^2)/2 = A A = -AG + AT - AF AG = mgh = 1.47 J AT = k/2*h0^2 = 0.0125 J AF = fmg*cos(60)*h0 = 0.0735 J A = -AG*cos(30) + AT - AF = -1.334 A-C (mv1^2)/2-(mv0^2)/2 = A A = AG C NC + Gcos(45) - Φn = 0