Recent content by adipta_datta

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    Problem on Second Law of Thermodynamics

    Below is the thing which I have attempted: eta of Heat engine 2(between the reservoirs A&C)=(Ta-Tc)/Ta therefore,eta of heat engine 1(between reservoirs A,B&C)=\alpha[(Ta-Tc)/Ta] where eta is the efficiency of the heat engine. Now heat absorbed by heat engine 1=2Q1 Heat rejected by heat...
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    Problem on Second Law of Thermodynamics

    A reversible engine works between three thermal reservoirs-A,B and C.The engine absorbs an equal amount of heat from the thermal reservoirs A & B kept at temperatures Ta and Tb respectively,and rejects heat to the thermal reservoir C kept at temperature Tc.The efficiency of the engine is\alpha...
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    Problem on Second Law of Thermodynamics

    ok.thanks for the advice and your help.
  4. A

    Problem on Second Law of Thermodynamics

    A reversible engine works between three thermal reservoirs-A,B and C.The engine absorbs an equal amount of heat from the thermal reservoirs A & B kept at temperatures Ta and Tb respectively,and rejects heat to the thermal reservoir C kept at temperature Tc.The efficiency of the engine is \alpha...