Recent content by Aenion

No, I'm sorry your right i meant W[SIZE="1"]man = W[SIZE="1"]Ground Which would then still be Wman = Wground 726N(1m) = Fground(.005m) 726/.005 = Fground 145200 = Fground and that can be rounded to 1.5 X 10^5 Which after i Re read your comment i saw that you had already stated...

Yes I believe I am are you talking about PEi + KEi = PEf + KEf ? but i do see what you are saying and how i didnt account for the work done by the ground. In order to find the force exerted by the ground though isn't it possible for me to set the man's force of 726N equal to the work done by...

Well I thought maybe at fist i could use the work-Kinetic energy thm. and solve for the force but the force i was solving by using F(delta X) = 1/2MVf^2 was the force of the man on the ground (726N). Then i looked at it if the man was standing stationary on the ground he would then be currently...

Homework Statement A 75Kg man jumps from a window 1.0m above the side walk. if the man jumps with his knees and ankles locked, the only cushion for his fall is approximately 0.50cm in the pads of his feet. Calculate the average force exerted on him by the ground in this situation...