Homework Statement
A capacitor of capacitance 5µF is charged to 24 V and another capacitor of capacitance 6µF is charged to 12 V. The positive plate of first capacitor is now connected to negative plate of second and vice versa.Fid ew charges on capacitor.
Homework Equations
Q=CV
E= QV/2 =...
A capacitor is connected to a battery. If a person pulls the plate to increase the distance by 2d the decrease in energy between the plates is E. We observe energy gained by battery is 2E. From where does extra energy E come from.?
Actually I just started learning electrostatics. In our texts it is mentioned that electric field inside a conductor must be 0. But nothing is mentioned if it has a charge inside it. So I just asked out of curiosity. Btw can you say why it won't be zero?