Recent content by AlanWWW

Thx

After the adjustment , i got h Then I calculate the angle: arcosθ=(0.3-h)/0.3 And I got θ = 73.6 degree, which is wrong However If I do not calculate the transitional kinetic energy: KE_rotational = mgh I got the exact correct answer Is there any conceptual mistake I made?

The angular impulse = radius of rotation *linear impulse

No... there is problem about the value of h I calculate with following steps: I = 0.5*m*(r^2) + m*(r^2) <---first r is 0.5 and second r is 0.3 I = 1.075 I*w = impulse w = 4.651 KE_initial = KE_final 0.5*I*(w^2) + 0.5*m*(v^2) = mgh 0.5*I*(w^2) + 0.5*m*(r^2)*(w^2) = mgh <--r is 0.3 h =...

h is the vertical displacement of center of mass The question gave impulse only, so I think the impulse-momentum theorem should be used

Homework Statement A circular plate with radius 0.5 m and mass 5 kg is hung on the wall, fixed at a point that is 0.3 m above its center. The plate can freely rotate about the fixed point with no friction. A very short-duration impulse of 5 N sec, along a direction that is tangential to the...