Recent content by alexcc17

I got it thanks though

Homework Statement i.5 - i Homework Equations zc=ec log(z) z1/n=exp[(1/n) log(z)], n is in integer The Attempt at a Solution letting c=.5-i and z=i so zc=e(.5-i) log(i) = e.5 log(i)*e-i log(i) from the second equation I reduced it to: i.5*e-i log(i) but I'm not sure...

Homework Statement Find all values of z such that ez=1+i√3Homework Equations The Attempt at a Solution I have no idea how to do this. I was going to start with ez=exeiy and try to figure something out from that, but I'm not seeing anything. I checked the solution shown below, but I'm really...

The boundary is {z ε: Re(z^2)=1} and there is no closure since it's an open set?

Would the interior be: {z ε: Re(z^2)>1} so the set itself, since the boundary is what it approaches and isn't actually part of the set.

Like this?

So you mean every point on that hyperbola excluding where each axis is 1,-1?

The set is given {z ε: Re(z^2)>1} so x^2 -y^2=52 or anything larger than 1 which is still a hyperbola.

Homework Statement Determine the interior, the boundary and the closure of the set {z ε: Re(z2>1} Is the interior of the set path-connected? Homework Equations Re(z)=(z+z*)/2 The Attempt at a Solution Alright so z2=(x+iy)(x+iy)=x2+2ixy-y2 so Re(x2+2ixy-y2)= x2-y2 >1 So would...

Wasn't sure if that applied to matrices. Thanks

Would it just be p_299*T to get p_300?

Homework Statement Suppose that the initial vector P0 is not given and instead we are given that at time t=299 the state vector is P_299=[.1 .1 .8]. Than find P_300, the state vector at time t=300 Homework Equations I also know from the problem it is referencing that the transition...

It does. Thanks

Ok, I think I have it. The transition matrix should be: [.3 .7] [.4 .6] Right?

Homework Statement The problem is in the attachment, but I'll try and rewrite it... Suppose for a Markov Chain with two states, we get the following results. 1. If P0=[0 1] then P1=[.4 .6] 2. If P0=[4/11 7/11] then P0=P1=P2=...and so on. With this information, find the transition...