Recent content by alfie254

Thank you everybody, now I understand. Alfie

Ok, I have a number to the power of another, say 2^3 which of course is 8. Question is if you have 2^n = 8 how do you calculate n?, this is obviously simple for the example but say if I needed to calculate n in 2^n = 1000 how do I do this either on paper or using a calculator, I've searched the...

Thanks! :smile: Alfie

Ok, an easy one I think? I am given an equation to work out the strain on a beam, the dimensions of the beam are in the equation (obviously) and in the question these are given in mm and cm, am I right in thinking all the measurements in the equation need to be in m and the question is trying to...

Thanks again Cel. Ok, so if the conductance of the circuit does not change then it is pretty straightforward...but I had considered this before as a worked example in the text had conductance not changing but this was for a circuit which did not have a new component added, whereas this one...

Ok Cel, thank you, I should of specified the question better but I thought i had the thing sussed out once I worked out how to reduce the polar current by 20% The question is related to the admittance triangle Y²=G²+B² The load on the circuit is represented in polar form by 3 admittances...

Ah cool so its a bit of a trick question then? What it asks is: What value of capacitor is required in parallel to the load to reduce the supply current of 95 L-46.37º by 20% and the new power factor with the capacitor in circuit. So from my answers I have devised a value for the capacitor...

Thank you for the reply, I appreciate it, I'm even more confused now as the full question relates to impedance/ admitance triangles (Z²=R²+X² / Y²=G²+B²) and asks for the new power factor of the system if the current drops 20%, however as the power factor is derived from the cos of the phase...

Homework Statement reduce a current in its polar form 95 -46.37° by 20% Homework Equations The Attempt at a Solution When dividing a polar number by a scalar one you just divide the magnitude by the scalar, the phase will remain unchanged, so to reduce the polar value by 20%...