Recent content by Am_o

So what I do is: Vt=Vr+VL Vr= I*R VL= -L(di/st) ∴ Vt=(I*R)+(-Ldi/dt) So put in the variables given: 15v=(4A*R)+(-L(0.5A/s)) increasing rate 10v=(4A*R)+(-L(-0.5A/s)) decreasing rate Then solve for L & R like?

Homework Statement When the current in the portion of the circuit shown in the figure below is 4.00 A and increases at a rate of 0.500 A/s, the measured voltage is ∆ = 15.0 V. When the current is 4.00 A and decreases at the rate of 0.500 A/s, the measured voltage is ∆ = 10.0 V. Calculate the...