Recent content by AMRIT GAUTAM

Thank you guys for idea Finally solved it first used formula 4/3 pi R^3= n 4/3 pi r ^3 Which gave R= n^(1/3)r ...(1) And potential V= k Q/R ...(2) where Q = 6q-2q since they are provided potential of different sign And gave Combining 1 and 2 and puting...

I know but this methode only useful for similar charge only searched whole internet can't find right answer. All links leads to same potential problem only i tried it myself bt couldnt

Um i solve it using formula V=n^(2/3) vs where n is no of drops and vs is potential of each drop but it works for condition when all are provided same potential

Six mercury drops of equal size given potential of +3v and two other drops are given -3v potential. If they coalesce what is final potential This question had been eating my brain i know solution if they are given same potential but what to do when they have different potential

hi everyone i am planning to study some research paper on string theory but i am confused where to search for latest research papers, how can i download them?