Recent content by andrewvidler

Hi - how about this one? I am confused as to what constitutes a different group. I mean how far do go along the separate branches from the ceontre to say that is a differernt substituent. this is one where it days there are 3. I know where they are but i don't see why

Hi Borek - i know the basics, ie a carbon with 4 different substituents is a chiral carbon, however i have been given complex molecules that have multiple chirality centres and i cannot see them. For instance the attached image has 4 - but i can't see why.

I am having a lot of trouble with this. Does anyone know how to identify the chiral centres in the following attached molecule?

thanks - my final units are 453 kg/sm. any chance on helping me how to get this into pascals which are measured in mPa s?

Hi i have done all the work for this problem calculating viscosity and i come to the last part where i need to manipulate and cancel out units to come to a final solution. The equation works out as viscosity = 0.0042m^2 x 9.8m/s/s x 11,401.4kg/m^3 all divided by 1.034466m/s viscosity is...