Recent content by AnkleBreakeer

g) Factor of Safety= (Buckling stress)/(working stress) Cross sectional area=(pi)〖((59/2000)〗^2-(44.25/2000)^2) Cross sectional area=1.196*〖10〗^(-3) m^2 Buckling stress=(200.65*〖10〗^3)/(1.196*〖10〗^(-3) )=167.8*〖10〗^6 Pa Working stress=5000/(1.196*〖10〗^(-3) )=4.18*〖10〗^6 Pa Factor of...

My working a) Steel A36 should be used as our lecturer said so. b) I researched a little and found that 4 is a pretty safe estimate for the safety factor c) Factor of safety= (shear stress)/(maximum allowable stress) 4=(145*〖10〗^6)/(maximum allowable stress) maximum allowable...

Homework Statement As an engineer you are tasked to design a 2m long shaft which is to be manufactured either as a solid circular bar or circular tube. The shaft is required to transmit a torque of 1000Nm without exceeding the allowable strength of the material. Address the following: a)...