Recent content by Anonymous243

How does it work? I mean, I don't understand how that equation derives the electrostatic potential energy.. Could you please explain it more in detail?

So do I have to calculate the charge $$Q(r)=-e \int_0^r 4\pi r^2 \rho(r)dr,$$ which is the the charge of the cloud when its radius is ##r## and then calculate the electric field ##E(s) (s>r)## using Gauss's law like this: $$E(s)= \frac {Q(r)} {4\pi \varepsilon_0 s^2}?$$ Then I can derive...

Well, I'm not so sure..

Yes! First, we have to get the function of the electric field. Let's say that -e is the charge of an electron. Then, $$dQ=-4e\pi r^2 \rho_0 \left(1-\frac r R_0 \right) dr.$$ If we think of a spherical gaussian surface with radius r (0<r<R₀), $$\varepsilon_0 E(r) 4\pi r^2 = \int_0^r -4e \pi r^2...

Hi, I'm new here, so I don't know how to write mathematical equations, and I may not be fully aware of the rules here, so I'm sorry if I made a mistake. I know how to calculate the electrostatic potential energy of a countable number of charged particles, but I don't know how to calculate the...