Recent content by Aokei

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    If log₃m = n, how do I find log₃m⁴ in terms of n?

    Mkay, thank you for the aid, I'll see how it is tomorrow.
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    If log₃m = n, how do I find log₃m⁴ in terms of n?

    Since I'm having serious conceptual problems, can you show me the process to get the correct answer? The answer in the textbook is 4n.
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    If log₃m = n, how do I find log₃m⁴ in terms of n?

    I'm having trouble understanding the exponent part. In this situation a≠b. Adding the forth power to (3^n) changes the equation. Maybe if I rewrite log_3 m^4 as log_3(m^4) might help. I'm confused as to how you move the exponent. The way I think of it is, the exponent moves with the variable...
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    If log₃m = n, how do I find log₃m⁴ in terms of n?

    So log_3 m=n means 3^n=m. - I understand this part. m^4=(3^n)^4 - this confuses me a bit, since there's a fourth power on both sides. I thought log_3 m^4 = n was: 3^n = m^4.
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    If log₃m = n, how do I find log₃m⁴ in terms of n?

    Nope, my class was only told exponential form and logarithmic form, no rules of logarithms so far. We're only on the first part of the logarithm unit, the question above is a part of the "Extend" section of the chapter, which thought provoking questions than the others.
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    If log₃m = n, how do I find log₃m⁴ in terms of n?

    Homework Statement "If log3m = n, then determine log3m4, in terms of n." 2. The attempt at a solution I'm pretty much clueless as how to set up the equation, and what 'in terms of n' means. My guess is log3m = log3m4, but I'm confused about what to do next. The answer in the textbook...
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