Thank you for your reply Kurdt.
I was able to figure out the problem this morning after a good nights rest :)
I found the velocity in the vertical direction and from there it's pretty simple to find the max height using
h= v{y}^2(sin^2(theta)) / 2g
and in this case theta was 90...
Homework Statement
A science student is riding on a flatcar of a train traveling along a straight horizontal tract at a constant speed of 10.0m/s. The student throws a ball along a path that she judges to make an initial angle of 60.0degrees with the horizontal and to be in line with the...