Recent content by Artj0m

This has been a great help! Thanks! :)

Thanks you guys! :)

So the equation we made is not useful? Or did the equation had to be something like this? mA+B = ρA*VA + ρB*VB

I'm stuck haha What do you mean? I'm not sure I understand you correctly. ( I've changed the M into W, so it fits the equation ρ = ρw * W/(W-T))

That's just W - WG right?

For the ρ, I have: ρg + a = [(WG + WA) / (WG*ρA + WA*ρG)] * (ρG + ρA) So I will equate it with ρw * W/(W-T) and then I should get the correct answer right?

Oh I see! Because of ρ = M / V But how does this help me in the exercise?

Just (ρA + ρB) right?

VA+B = mA / ρA + mB / ρB = (mA*ρB + mB*ρA) / (ρA + ρB)

So ρa/ρw = W - Wg / W - T I don't understand how I should add this equation with the Aluminium one.

I understand, I'm just struggling with the fact that I don't know where in the equation I have to place the Wgold. Could you give a clue?

I've read it and I have come to this. Like you said, I only started with the aluminium ρa/ρw = W/(W-T) This leads to W - [(ρa/ρw) * (W - T)] = 0 This comes pretty close to the answer in my book: Wg = (ρg / (ρg - ρalu)) * (W - (ρa/ρw) * (W - T))

If I apply the formula, I know that Vw = mw / ρw = malu / ρw Because of the Buoyancy, B = Walu = mw * g = malu * g So mw = malu

The amount of volume the water rises is equal to the volume of the object. That I understand. I'm just having troubles with writing a good equation.

Yes, the buoyancy. I understand the concept, but the problem is that I eventually have to separate the two metals.