Recent content by Asuncion
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Physics I Midterm Exam in 2 days
Since you put it that way. Δv=v. However, the problem states that the speed doubled plus its going in the opposite direction, that's where I got the -2.- Asuncion
- Post #26
- Forum: Introductory Physics Homework Help
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Physics I Midterm Exam in 2 days
Thanks SHISHKABOB! I have to take a break for an hr or two. Gotta get dinner ready for my husband and three kids, but I'll be back! ;)- Asuncion
- Post #25
- Forum: Introductory Physics Homework Help
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Adding Normal Forces for Net Force Calculation
You are so right e^(i Pi)+1=0! Thank you :smile:- Asuncion
- Post #23
- Forum: Introductory Physics Homework Help
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Physics I Midterm Exam in 2 days
3. I'm going to try. Going back to pre-calculus-solving exponential equations w/ same base. Let original velocity = u. v=\frac{-2u}{.45} a=\frac{-3u}{.45} Then \frac{-2}{-3} = .66666667 or 6.7s^{-1} or 6.7*10^{-1}...- Asuncion
- Post #22
- Forum: Introductory Physics Homework Help
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Physics I Midterm Exam in 2 days
1. speed_{avg} = 71 mph and velocity_{avg} = 44 mph. Therefore, 71 mph -44 mph = 27 mph.- Asuncion
- Post #20
- Forum: Introductory Physics Homework Help
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Physics I Midterm Exam in 2 days
I have to admit this one was tricky because normally (well the way I learned in chemistry) the given units come first then the desired conversion factor comes next. In this case the desired conversion factor came first (or as you say take the reciprocal) then the given. Well We knocked #2 out...- Asuncion
- Post #18
- Forum: Introductory Physics Homework Help
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Physics I Midterm Exam in 2 days
Oh SHISHKABOB Your the best! I found my mistake I shouldn't have been separating 6.7 * 10^{7}. thanks again SHISKABOB I was making it too complicated! I'm trying not to I always make the easy stuff complicated, but the complicated stuff comes easy... why me :rolleyes:- Asuncion
- Post #17
- Forum: Introductory Physics Homework Help
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Physics I Midterm Exam in 2 days
2. Sorry, if you haven't figured it out already I'm a Visual Learner. But Thank that you God, a Light bulb just went off in my head. \frac{1 cal}{10^{-9} sec} \frac{1 sec}{6.7 *10^{7}} When you add the exponents you get \frac{1}{6.7*^10{-2}sec }. YAY!- Asuncion
- Post #15
- Forum: Introductory Physics Homework Help
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Physics I Midterm Exam in 2 days
2. Here's how I set it up but I still come out with the wrong answer. \frac{1 cal}{10^{-9}} \frac{1 sec}{6.7*10^{7}}- Asuncion
- Post #14
- Forum: Introductory Physics Homework Help
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Physics I Midterm Exam in 2 days
Okay so maybe I need more practice. :/- Asuncion
- Post #12
- Forum: Introductory Physics Homework Help
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Physics I Midterm Exam in 2 days
2. 1 cal \frac{1 ns}{10^{9-}} \frac^{7}{10}{6.7 cal}- Asuncion
- Post #11
- Forum: Introductory Physics Homework Help
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Physics I Midterm Exam in 2 days
Aww HA! Thanks :!)- Asuncion
- Post #10
- Forum: Introductory Physics Homework Help
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Physics I Midterm Exam in 2 days
\frac{calulations}{seconds}- Asuncion
- Post #9
- Forum: Introductory Physics Homework Help
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Physics I Midterm Exam in 2 days
2. Here's how I wrote it down on paper: 1 cal , 1 ns / 10^-9 sec, 10 ^7 sec/ 6.7 cal = .15 cal / 10^-2. Everything cancels out expect for nanosecond. Then after subtracting the exponents I get 10^-2. Instead of dividing by .15 cal / 10 ^-2 I flipped the numerator and denominator. 10^-2/ .15...- Asuncion
- Post #8
- Forum: Introductory Physics Homework Help
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Physics I Midterm Exam in 2 days
Oops I was playing around with the format. Trying to get my fraction format like yours instead of using the *^/ symbols. gets confusing.- Asuncion
- Post #6
- Forum: Introductory Physics Homework Help