Recent content by atomsmyth

Yeah, I meant to post last night when I saw that. It was sq.rt(2)/6! Thanks for the help.

I don't see where it's easier with the square root symbol grouping every into one term.. Could you show me what you did?

Oh, and I did it in polar coordinates to eliminate the denominators in the integrand; looking at this in rectangular coordinates is much more work..

I'll rework it in rectangular coordinates, but the problem doesn't state to only use the first octant, but I don't see where the other octant comes into the picture. If the Domain in x-y is only in the region between y=x and y=x^2, then it would only be in quadrant 1..unless we use the negative...

Oh, my new answer is √{2}/2.

Hello, everyone. I've used this forum several times in the past for help with problems or just to see other vantage points on a subject. This is my first post, so please bare with me in trying to format my post correctly. I'm studying for my final exam in Calculus III next week and am working...