Recent content by Atx

Always trust picture. A is getting the force. I've modeled the forces as a free body diagram. The forces excerted on B is x: T(tension)-0.3*mg = m*a (where a is the same accelleration as the one on block A). B in y direction is mg-mg=0 which means there is no accelleration in y-direction for...

I'd appreciate any hints, I've been stuck on this problem for a while.:frown:

wow, my bad. :blushing: A force F is pulling on B in the right horizontal direction. The mass of A is 5.00 kg, the mass of B is 3.00 kg. Static friction between all surfaces is 0.600 , kinetic friction is 0.400. Assuming the blocks are at rest, for what value of F will the blocks be put...

Homework Statement [PLAIN]http://img693.imageshack.us/img693/8219/utennavnu.png Homework Equations n= normal force µ*n=friction F=ma. T = tension , mA = mass of A, mB mass of B The Attempt at a Solution a) Static friction should be used. Forces on brick A : x: T - µ*mg=0 y...