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    How to Solve Calculus Problems with Recurrence: A Step-by-Step Explanation

    i think solution with récurrence for n=1 then 1=2¨¨^0(2x0 +1) true suppose that n=2¨^p(2q+1) is true shows that n+1=2^p( 2q +1)? n+1=2¨^p(2q+1) +1 ⇒ ??
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