Recent content by avoinvents

Than you for all your help :smile:

Is this the correct answer? 0.000152995 psi Please say it is. thanks again

OK, with the online converter, I selected from 10 grams – forces /centimeter ^2 converts to 0.142233433 PSI, I then divide this into the surface area of the mat. The final pressure needs to be in PSI. So far is this correct. 10 grams = 0.098 Newton’s. Mat size is 12” x 12” = 144 square...

10 grams = 0.093 Newton’s, 0.093 Newton’s = 0.142233433 PSI. Then I divide 0.142233433 by the surface of the mat with is which is 30cm x 30cm = 900 square cm. This would mean the pressure per cm is 0.000158. Can anyone confirm if I’m correct please? I used this online converter to convert...

Lets say that the mat would only be used for 1-2 minutes at anyone time and we were to use a gauge type pressure sensor, this would automatically calibrate the barometric pressure there we should get an accurate representation of the 10g on the mat. The idea of using a U tube would work to a...

It’s become more than obsession of mine now to make this work if it can. I’m not sure if a product like this would have its use or not, never the less, I would still like to mat it if possible. Berkeman: “What is the pressure change inside your mat for a 10g weight being added on top of...

The idea using a mat with air inside was of more interest to me. If it can be done, can anyone please point me in the right direction?

Do you think that a mat could be made as sensitive as a barometer? My idea is designing a inflatable mat that could determine weight of say 10grams placed on it and display an accurate reading of the weight shown on a LCD panel. Many thanks for your help in advance.

Sorry to be a pain, but i need further help with this and please bear in mind that i have never done this before. I understand the part where i have to convert the weight into force but i have no idea on how to convert the force into air pressure. Could someone please try and explain to me...

If I have a mat of air 12”x 12” with 98mN of force applied to it, I need to divide 98mN by 144 = 0.68. Would it be 0.68 PSI, millibar etc?

OK, so to get my pressure/force, I need to multiply 10 grams by 9.8066 = 98mN, is this correct? Then I need to divide 98mN by the surface area to give me my air pressure? I have drawn 2 pictures I would like to show you, but I’m not sure how to upload them to you? May I have an email address...

Hi, I hope you can help me please. I have an AA battery here that has a weight of 10 grams, I would like to know what 10 grams of weight is equals to in air pressure like mill bar or PSI, can you help please? Many thanks in advance Christopher