Alright, maybe I figured it out. I got x=7. Let me explain:
2x/7=2x^2
Divide each side by two
(2x/7)/2=(2x^2)/2
simplify to:
x/7=x^2
Divide each side by x
(x/7)/x= (x^2)/x
Simplify to:
7=x
I'm a bit confused on when you can cancel while dividing. Is it just when the top & bottom mach...
Starting from the beginning or where I currently have the equation?
Alright, maybe I figured it out. I got x=7. Let me explain:
2x/7=2x^2 Divide each side by two
(2x/7)/2=(2x^2)/2 simplify to:
x/7=x^2 Divide each side by x
(x/7)/x= (x^2)/x Simplify to:
7=x
Re: Help Please :)
Absolutely, I have tried to break up the right side of the equation, so that the equation looks like: 2x/7= (2x)(2x)
After this, I divided each side by 2x:
(2x/7)/2x=(2x^2)/2x
After that, I'm pretty stuck.