Recent content by babcockkw

Alright, maybe I figured it out. I got x=7. Let me explain: 2x/7=2x^2 Divide each side by two (2x/7)/2=(2x^2)/2 simplify to: x/7=x^2 Divide each side by x (x/7)/x= (x^2)/x Simplify to: 7=x I'm a bit confused on when you can cancel while dividing. Is it just when the top & bottom mach...

Starting from the beginning or where I currently have the equation? Alright, maybe I figured it out. I got x=7. Let me explain: 2x/7=2x^2 Divide each side by two (2x/7)/2=(2x^2)/2 simplify to: x/7=x^2 Divide each side by x (x/7)/x= (x^2)/x Simplify to: 7=x

Re: Help Please :) Absolutely, I have tried to break up the right side of the equation, so that the equation looks like: 2x/7= (2x)(2x) After this, I divided each side by 2x: (2x/7)/2x=(2x^2)/2x After that, I'm pretty stuck.

So here is the question: 2x/7=2x^2