Recent content by badatmath

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    MHB Finding Domain of f(x)=\frac{1}{x^{2}-x-6}

    I figured it out! $$x^2-x-6=0$$ $$(x-3)(x+2)=0$$ $$x\in\{-2,3\}$$ And so the domain, in interval notation, is: $$(-\infty,-2)\,\cup\,(-2,3)\,\cup\,(3,\infty)$$
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    MHB Finding Domain of f(x)=\frac{1}{x^{2}-x-6}

    So I add 6. That makes x^2-x=6, and then what?
  3. B

    MHB Finding Domain of f(x)=\frac{1}{x^{2}-x-6}

    I'm supposed to find the domain of this function, I know I'm supposed to set the denominator equal to 0 but I don't know what to do after that, please help! $$f(x)=\frac{1}{x^{2}-x-6}$$ I can't figure out how to make this look like a real fraction but it's supposed to be 1 over x squared minus...