Recent content by bakamanju

I believe I found the velocity at midpoint of the distance that is traveled by the projectile. By using (Vfy^2 - Vo^2)/ (2*-9.8 m/s^2), I was able to calculate the maximum height because Vfy would be 0 at the apex of the projectile's distance. I got 45.92 meters for the maximum height. Do I...

Thank you very much for the assistance. I think I understand it now!

Homework Statement In each case, draw a set of graphs for the vertical and horizontal components of motion. Also draw a motion map of the vertical and horizontal components of motion. A projectile is launched with a speed of 30 m/s at an angle of 30 degrees. At a point which is ½ the way down...